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3x^2+25=-416
We move all terms to the left:
3x^2+25-(-416)=0
We add all the numbers together, and all the variables
3x^2+441=0
a = 3; b = 0; c = +441;
Δ = b2-4ac
Δ = 02-4·3·441
Δ = -5292
Delta is less than zero, so there is no solution for the equation
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